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Math Help - Hypothesis Testing for Two Proportions

  1. #1
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    Hypothesis Testing for Two Proportions

    I have a problem I am doing for hw for my Data Analysis II course, which involves the use of Minitab and need help. I solved it, but need to know if I had done it correctly.

    Problem: A random sample of 78 women ages 21-29 in Denver showed that 23 have a college degree. Another random sample of 73 men in Denver in the same age group showed that 20 have a college degree. Based on information from Educational Attainment in the United States, Bureau of the Census, does this indicate that the proportion of Denver women ages 21-29 with college degrees is more than Denver men in this same age group?

    My Minitab output:

    Test and CI for Two Proportions

    Sample X N Sample p
    1 23 78 0.294872
    2 20 73 0.273973


    Difference = p (1) - p (2)
    Estimate for difference: 0.0208992
    95% lower bound for difference: -0.0998659
    Test for difference = 0 (vs > 0): Z = 0.28 P-Value = 0.388

    My Answer:
    Decision: 0.388 > 0.05 , so Fail to reject the null hypothesis

    Conclusion: There exists sufficient evidence at the 5% level of significance that the true proportion of Denver women ages 21-29 with college degrees is more than the true proportion of Denver men ages 21-29 with college degrees.
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  2. #2
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    Re: Hypothesis Testing for Two Proportions

    Decision is correct, fail to reject H_0 and therefore conclude there is no evidence to suggest the true proportion of women with college degrees is greater than the true proportion of men with college degrees.
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  3. #3
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    Re: Hypothesis Testing for Two Proportions

    Sorry, I meant to type insufficient evidence. My bad...thanks for the help!
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