Re: ball throwing question..

Quote:

Originally Posted by

**transgalactic** i have 6 balls .

balls 1-3 are white, balls 4,5 are red, ball 6 is blue

we throw these balls into 5 holes numerated 1-5

what is the probability that in hole number 3 we get only red balls

and there is no red balls in the other holes

i saw another student soluton and it says

$\displaystyle \frac{1^24^4}{5^6}$ cant understand the numerator

That answer assumes a *function model*.

There are $\displaystyle 5^6$ functions from a set of six to a set of five.

There is one way to put the balls 4&5 into hole #3.

There are $\displaystyle 4^4$ ways to put the other balls into the other holes.

Re: ball throwing question..

i forgot to mention that every hole can contain at most 6 balls

Re: ball throwing question..

Quote:

Originally Posted by

**transgalactic** i forgot to mention that every hole can contain at most 6 balls

That fact does not change the answer in any way.

All six balls can be in the same hole.