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Math Help - mean calculation (advance type)

  1. #1
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    mean calculation (advance type)

    '"the mean of 200items is 50, later it was discovered that two of the items used to derived the mean i.e 92 and 8 were actually 192 and 88. what is the corrected mean after replacing the right items (192and 88)?". have tried all i could but could not arrived at the answer, what is it am missing here i mean right procedure, contributions will be highly appreciated.

    this is for practice purpose. thanks
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  2. #2
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    Re: mean calculation (advance type)

    Is this a problem in advanced probability or in basic algebra?

    Let S be the sum of all items except for the two items in question. Then \frac{S+92+8}{200}=50. From here you can find S and calculate \frac{S+192+88}{200}. Actually, \frac{S+192+88}{200}=\frac{S+92+8}{200}+\frac{180}  {200}=50.9.
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