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Math Help - propability, train stop

  1. #1
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    propability, train stop

    Hi

    I am sorry, I have to make a correction on this opening mail;

    There are 5 train stops and 2 passengers. What is propability that EITHER ONE DOES NOT get off
    on first two stops ( stop 1 and stop 2 ) ?

    - My solution is 1/5^2 + 1/5^2 = 2/25


    And propability that both passengers DO NOT get off
    on first three stops ( stop 1, stop 2, stop 3 ) ?

    - My solution is 1/5^2 + 1/5^2 + 1/5^2 = 3/25

    I don't know are my solutions correct?
    Last edited by stevetall; December 6th 2011 at 04:33 AM.
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  2. #2
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    Re: propability, train stop

    Quote Originally Posted by stevetall View Post
    There are 5 train stops and 2 passengers. What is propability that both passengers DO NOT get off
    on first two stops ( stop 1 and stop 2 ) ?
    Does that mean that both do not get off at stop 1 and both do not get off at stop 2?
    In other words the one could at 1 and the other at 2, but just not both at 1 or 2?
    Last edited by Plato; December 6th 2011 at 04:04 AM.
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  3. #3
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    Re: propability, train stop

    I see. Then it must be;
    propability that both passengers DO NOT get off
    on first two stops ( stop 1 AND stop 2 ) ?

    - 1/5^2 = 1/25
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  4. #4
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    Re: propability, train stop

    "Does that mean that both do not get off at stop 1 and both do not get off at stop 2?" - YES

    Propability that one can can get off on any stop is clearly 1/5.


    And each of those two can get off on any stop he wants. 5 stops and two passengers, indeed.

    First I thought 1/5^2 + 1/5^2

    But now I think 1/5^2. But don't know...
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