Joint Probability Density Function/Finding expected Value
The Joint Probability Density Function of X and Y is
f(x,y) = c(y^2 - 64x^2)e^-y, -y/8<= x <= y/8, 0<y<infinity
So the integral would look something like this?
Find c and the expected Value of X.
But I don't know how where to go from here or how to get the expected value
C is supposed to be 1 and E[X] should be 0.
Re: Joint Probability Density Function/Finding expected Value
If you have studied probability density functions carefully, the joint pdf should integrate to 1(by definition). so solve for "c" using the following (its simple integration), and then recall the definition of expected value to find E[X]..
Originally Posted by bjnovak