Now onto more serious matters. For the 41 part we can look at the problem like this. If we just had to count the number of ways to arrange 3 digits we would have _ _ _
ways to do it.
But now we want to fix two digits in order to get 41 so we have
41 _ or
where we can put 0-9 in the _ this can happend a total of 18 ways. Now use the fundamental counting principle to finish part 1. Use the same trick for 2nd part.
What have you tried for the 2nd problem. Where are you stuck?