This is a case of “Why reinvent the wheel”?
Have you done a web-search for poker-hands?
There is such surfeit of information out there; it is a waste of resources to try to answer such a broad question.
Heyo, so I've been doing a little extra probability work for a gaming series since in general I like to know the odds of something before I get involved. Basically I've been through all the Poker probability stuff on Wikipedia and a few other sights but have yet to find what I want and figuring it out myself has been really hard. Basically I'm looking to figure out the number of hands (or % chance of a hand* coming up) out of 6,7,8,9, and 10 cards. I've been able to find straight odds on the internet pretty easy but little explination as to what the cominatorics are for 7, 8, 9 and 10 hands. The *really* tricky part really is I want 2 sets of data for each hand size. The first set where there are 2 Jokers in the deck but they represent nil cards (completely useless) and the second set where One joker is considered "wild" and the other is still nil. If anyones done this before I'd love to hear about it (or where I can read about it) if not anyone have a decent way of explaining the combos for different hands with greater hand size, plus wilds? I'm pretty sure the data for sets with 2 "bad" jokers is just redividing the possible number of each hand by 54 choose 6 instead of 52 choose 6 but I'm not even sure thats right.
Any thoughts?
(*PS I've defined "hands" as Lower than Ace, Ace, Pair, Jacks or Better, 2 Pair, 3 of a kind, Straight, Flush, Full House, Four of a Kind, Straight Flush, 5 of a kind)
I suppose my real problem is adding in the "nil" card. If you take all the standard 6 combination poker hands you have 20,358,520 possible hands. Adding 2 jokers that act as dead cards ups the total hand size to 25,827,165 possible hands. What I'm not sure of is how the number of hands change when those cards are added. Since some of the hands with these jokers will still be viable hands (ace or better) I assume I can't just add the difference of possible hands to the fail pile and get accurate results. Also I haven't found anyone thats done this before on the web most just deal with jokers acting as wild cards.