It is a long time since I have worked on probabilities and to my dismay I cantquite get my head around how many permutations there are in the formularequired.
I tried the old p (1) X p (2) X p (3) X ... X etc. . . . but I dont think Iquite have it ..
This is my issue:-
Day one there are 57 spaces and the 57 numbers for these spaces are placedin a hat and drawn. Obviously the probability of drawing a seat is 1 in 57 and seattwo one in 56 as there is one less every time and so on.
What need to know is on Day two what is the probability of the draw repeatingitself exactly as day one?, as in the guy that pulled seat 1 pulls it also fromthe bag day two and all the way through that the guy will pull from the bag thesame seat as the day before ?
Can someone give me the answer and the formula before I get an injury doing this?