Originally Posted by
acasas4 The pdf of a random variable X is given by f(x)=c(1-x^2) for x element of (-1,1) (the element of symbol that looks like a curved E). For which values of c is this function actually a pdf? (c being a constant)
I know that in order for something to be a pdf it must meet the requirements that
p(x)>or= 0 for all x
and
the probabilities must sum to 1.
Where I am confused is by the element of (-1,1) I am not sure how to solve this with an interval.
Thanks to anyone who can help.
(I attached the equation in a word doc just in case my notation above is confusing)