Originally Posted by

**driver327** I just want to see if I am doing this right. the width is 0 to b, with f(x)=1/2, first I try to find b first, since the area is 1=bXh ----> 1=bX(1/2) ---> **b=2**.

Now, I have to find P(x<1) not to be confused with []

so, in this case, P(0<x<1)= (1-0)*(1/2)= **1/2**

P(1<x<4)

Since 4 is not in the function, it would be P(1<x<2), so, (2-1)*(1/2) = **1/2**

Lastly, since the width goes from 0 to 2, the median of the distribution is **1**.

I have a test in the morning and just want to get it right.

My side question is does it matter if it is greater or greater or equal to and vice-versa?

Thanks in advance.