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Math Help - Probability (with Bridge Hands)

  1. #1
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    Probability (with Bridge Hands)

    Hello this is my first posting so I hope I'm doing everything right!

    Okay so here is the question
    ----------------------------
    What is the probability that a Bridge Hande (13 cards) contains:
    a) 4 spades, 5 hearts, 3 diamonds, and 1 club

    b) no spades?

    c) a void? (at least one suit that is not represented)
    -----------------------------

    Now I think I answered the first one correctly, here it goes:
    -----------Answers-----------
    a) (13C4 * 13C5 * 13C3 * 13C1)/(52C13)
    = 0.00538779

    b) now im not sure for this one but (is it correct?)...
    (39C13)/(52C13) = 0.01279094804

    c) I thought that the answer to this would be the same as b) since one suit was not represented in b)
    -------------------------------

    Well thanks in advance to anyone who responds with some input, I'm not great at this stats stuff, and our prof is not giving great notes :S.
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  2. #2
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    Quote Originally Posted by shadarap View Post
    Hello this is my first posting so I hope I'm doing everything right!

    Okay so here is the question
    ----------------------------
    What is the probability that a Bridge Hande (13 cards) contains:
    a) 4 spades, 5 hearts, 3 diamonds, and 1 club

    b) no spades?

    c) a void? (at least one suit that is not represented)
    -----------------------------

    Now I think I answered the first one correctly, here it goes:
    -----------Answers-----------
    a) (13C4 * 13C5 * 13C3 * 13C1)/(52C13)
    = 0.00538779

    b) now im not sure for this one but (is it correct?)...
    (39C13)/(52C13) = 0.01279094804

    c) I thought that the answer to this would be the same as b) since one suit was not represented in b)
    -------------------------------

    Well thanks in advance to anyone who responds with some input, I'm not great at this stats stuff, and our prof is not giving great notes :S.
    For C, you will have to consider all the possibilities (I Think) and sum them

    For example, one possibility is that Two Suits Arnt Represented (And Two Are), and a way this can happen is to have All Clubs and one Diamond, so Spades and Hearts are not represented, thats one example.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    this question was answered already here.
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by shadarap View Post
    Hello this is my first posting so I hope I'm doing everything right!

    Okay so here is the question
    ----------------------------
    What is the probability that a Bridge Hande (13 cards) contains:

    b) no spades?

    c) a void? (at least one suit that is not represented)
    -----------------------------
    No spades:

    <br />
P(no\ spades)=\frac{39}{52}\times \frac{38}{51} .. \frac{27}{40} \approx 0.0128<br />

    Void:

    <br />
P(void)=4 \times P(no\ spades)<br />

    RonL
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