Originally Posted by

**nitros** Hello, sort of left an assignment to the last minute and am in desperate need of help

The results are in for the paper toss game and we have found that each participant's accuracy

(closeness to the coin) is dependent on the weight of the paper used as a ball. To show the

distinction, we have constructed the following contingency table from 200 samples:

Wc W

D 84 22

Dc 36 58

where W is the weight of the paper is less than 80 gsm, and D is the distance recorded is less

than or equal to 20 cm from a paper toss.

Note: you are allowed to use the text book probability tables when answering these questions.

When a table lookup has been performed, make it obvious by writing `from Table x', where x is

replaced by the table number used or the page number.

1 Probabilities

From the above contingency table, compute:

1. the probability that the distance is less than or equal to 20 cm and the weight is greater

than or equal to 80 gsm.

2. the probability that the distance is greater than 20 cm and the weight is greater than or

equal to 80 gsm.

3. the probability that the distance is less than or equal to 20 cm given that the weight is

greater than or equal to 80 gsm.

4. the probability that the distance is less than or equal to 20 cm given that the weight is less

that 80 gsm.

i dont get the whole table part, i know c = the event that it doesnt occur so am i suppose to put like probability 22 that both occur ? or is there an equation that i need to do? help will be greatly appreciated thanks.