I am waiting for your kind reply.
Q#1.What probability model is appropriate to describe a situation where 100 misprints are distributed randomly throughout the 100 pages of a book? For this model, what is the probability that a page observed at random will contain at least three misprints?
Is following method right?
n=100,p=0.01 and q=0.99
P(X=x)=(100Cx)(0.01)^x(0.99)^100-x, x=at least three misprints
These probabilites by means of the Poission approximation, using u=np=(100)(0.01)=1, are
P(X=x)=P(x;1)= 1.e^-1/x!, for at least three misprints.
Now I have the confusion in x value How i can calculate x value that is at least three misprints?
Note: clear the at least three.