The probability of scoring more than 90% on a certain end of year exam is 0.009.

Given the events are independant, find the probability of two tests scoring more than 90%.

Is it simply 0.009 x 0.009 = 0.000081?

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- August 10th 2011, 05:40 PMBushyindependant events
The probability of scoring more than 90% on a certain end of year exam is 0.009.

Given the events are independant, find the probability of two tests scoring more than 90%.

Is it simply 0.009 x 0.009 = 0.000081? - August 10th 2011, 06:52 PMTKHunnyRe: independant events
1) Who's getting the credit for these scores? Never mind...

2) Definition of independence p(A and B) = P(A) and P(B). I think you have it. - August 10th 2011, 06:57 PMBushyRe: independant events
- August 10th 2011, 07:06 PMTKHunnyRe: independant events
No worries. I was making fun of the wording, not your attitude.

Consult those defintions. They WILL save you!