I have the following questions.

The number of episodes per year of obtaining a certain disease follows poisson distribution has $\displaystyle \mu = 1.6$

**Find the probability of 3 or more episodes occuring over 2 years.**
I have $\displaystyle \mu = 1.6\times 2 = 3.2 $.

$\displaystyle \displaystyle P(X\geq 3) = 1- (P(X=0)+P(X=1)+P(X=2) )$

$\displaystyle = 1-\left(\frac{e^{3.2}\times 3.2^0}{0!}+\dots \right) = 0.62 $

Happy with that.

Find the probability of not getting any episodes of the disease in a certain year

so $\displaystyle \displaystyle P(X=0) = \frac{e^{3.2}\times 3.2^0}{0!}= 0.201897$

Also happy with that.

**What is the probability that 2 siblings will both have 3 or more episodes in the first to years?**
Is this binomial given p = 0.62 finding P(X=2)? but what would n be?

Or is it still poisson? maybe a different $\displaystyle \mu = 0.62$

Thx!