Results 1 to 7 of 7

Math Help - Application of Bayes rule / Girsanov density

  1. #1
    Newbie
    Joined
    Jun 2011
    Posts
    4

    Application of Bayes rule / Girsanov density

    Hello,
    I'm struggling with an application of bayes rule in a proof and I hope you can help me.

    At first some preliminaries:
    **P(t,T) is the price of a Zero-Coupon-Bond and B(t) is a discount factor<<--I think this isnt necessary to know in order to understand the problem below. But just for the completeness.


    We have a prop measure Q and define an equivalent prop. measure Q^Tby
    \frac{dQ^T}{dQ}=(P(0,T)B(T))^{-1}
    on a Filtration F_T, generated by Brownian Motions.

    In my context we have in particulary for t\leq T
    \frac{dQ^T}{dQ}|F_t=\frac{P(t,T)}{P(0,T)B(t)}


    Problem:
    Now one can show, that \frac{P(t,S)}{P(t,T)} is a martingale.
    But I do not understand the key step in the argumentation where bayes rule is used. The argumentation is for u\leq t\leq T\wedge S

    \mathbb{E}_{Q^T}\bigg[\frac{P(t,S)}{P(t,T)}\bigg| \mathcal{F}_u\bigg]=\frac{\mathbb{E}_\mathbb{Q}[\frac{P(t,T)}{P(0,T)B(t)}\frac{P(t,S)}{P(t,T)}| \mathcal{F}_u]}{\frac{P(u,T)}{P(0,T)B(u)}} = \frac{\frac{P(u,S)}{B(u)}}{\frac{P(u,T)}{B(u)}}= \frac{P(u,S)}{P(u,T)}

    The first equation is justified by bayes rule. But how?

    I think it should be something like:

    Represent the left Expectation through the Radon-Nikodym-Derivative and then use bayes, but I just can't complete it.


    P.s. If some more "context" is needed, just say. But, I think the problem above is just a pure stochastic question.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6

    Re: Application of Bayes rule / Girsanov density

    Hello,

    I'm trying and I can't really complete it... I think we have to go with multiplications and divisions of dQ's (and their conditionals, but that's the point where I'm in trouble).
    What do you call the Bayes rule ? I mean which version is that here ? And what's the rv in the first conditional expectation (the one you're calling "left"), it's t, isn't it ? I'm just making sure of it, as I've studied sto calc for not a so long time.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jun 2011
    Posts
    4

    Re: Application of Bayes rule / Girsanov density

    Hey Moo,
    thanks for your answer.

    Yeah, P(.,T)_t is the stochastic Process.
    I have the same understanding problem of which Bayes is meant. In the few proofs which all use the justification "Bayes rule", it is nowhere specified.

    I have the same troubles with the R-N-derivative, in particulary with the conditionals.

    Without conditions it is easier for the comprehension for me, when I write the exp.value as an integral. But I'm not sure, how to do this in the conditional case. That's my problem.

    P.s. Treffende Signatur für ein englischsprachiges Mathe-Forum.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6

    Re: Application of Bayes rule / Girsanov density

    Hi again !

    Sorry, actually ich sproche nicht Deutsch ! "Treffende" ??

    I happened to have a document about sto calc since yesterday (a course by Tomas Björk, for your information), for a different purpose than solving your problem and I told myself this morning : "Hey, what if I searched for Bayes in there, because Zeroy's problem seems easy yet unreachable ??" and it gave something great, called "the abstract bayes' formula". In our case, it exactly gives :
    (while noticing that \mathcal F_u\subseteq \mathcal F_t)

    E_{Q^T}\left[X\mid\mathcal F_u\right]=\frac{E_Q\left[\left(\frac{dQ^T}{dQ}|\mathcal F_u\right) X |\mathcal F_t \right]}{E_Q\left[\left(\frac{dQ^T}{dQ}|\mathcal F_t\right) |\mathcal F_u \right]}

    (I can't view the LaTeX images at work, I hope they're correct)
    And X is P(t,S)/P(t,T).

    And I think that to finish, you just have to deal with the denominator, which gives the answer since dQ^T/dQ | F_t shall be a martingale under the measure Q (thanks to Girsanov ?).

    If by tonight you still can't find the answer, just tell me, because with this Bayes' rule I'm a.s. that we can find the answer a.s.

    Auf wiedersen !
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Jun 2011
    Posts
    4

    Re: Application of Bayes rule / Girsanov density

    Hey Moo,

    yes, that's GREAT. It just looks like exactly the formula we need.

    Unfortunately I haven't much time these days(till sunday) for math. But I think maybe at least tonight I will take a little bit time and try to complete the proof, if it's not so hard anymore. And I think the rest shouldn't be.

    Again, big thanks for this Bayes Version. I have "Arbitrage theory" of thomas björk and will take a look on it, if I can find this Bayes in it. I'm pretty sure it should be in it.

    best regards!

    P.s. "Treffend" -> fitting, accurate, to the point.
    -> you have a well fitting signature for a math-forum ^^
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6

    Re: Application of Bayes rule / Girsanov density

    Quote Originally Posted by Zeroy View Post
    Hey Moo,

    yes, that's GREAT. It just looks like exactly the formula we need.

    Unfortunately I haven't much time these days(till sunday) for math. But I think maybe at least tonight I will take a little bit time and try to complete the proof, if it's not so hard anymore. And I think the rest shouldn't be.

    Again, big thanks for this Bayes Version. I have "Arbitrage theory" of thomas björk and will take a look on it, if I can find this Bayes in it. I'm pretty sure it should be in it.

    best regards!

    P.s. "Treffend" -> fitting, accurate, to the point.
    -> you have a well fitting signature for a math-forum ^^
    No, now I'm sure, it's pretty straightforward with this formula (which is, with the adapted notations, the very formula of this Bayes' rule).
    I found it on the 4th part of a pdf entitled "continuous time finance", which corresponds to some "chapter 10-12", so maybe this refers to the book you have ?

    The only point remaining is to show that dQ^T/dQ | F_t is a martingale under Q, which should be the case because Q is the risk neutral probability, or something like that ? That would be left to you

    I'm not sure if it's fitting, people aren't dumb, they may just ask dumb questions (which is not the case here, don't worry )

    See ya & good luck !
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    Jun 2011
    Posts
    4

    Re: Application of Bayes rule / Girsanov density

    haha, I'm stupid, I hadn't invest the 5 seconds, to look again at the Proof in the initial Post, because this bayes is exactly what stands there in the first equation. The denominaters are equal, because as you had seen properly, Q is the risk neutral measure, hence per definition the discounted Price Process P/B is a martingal.

    My comment regarding your signature was just ironcal.

    thanx again,
    gz
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Bayes Rule probability problem.
    Posted in the Statistics Forum
    Replies: 5
    Last Post: May 9th 2011, 09:58 AM
  2. Application of Bayes Theorem
    Posted in the Advanced Statistics Forum
    Replies: 4
    Last Post: August 29th 2009, 07:57 PM
  3. [SOLVED] bayes' rule
    Posted in the Statistics Forum
    Replies: 2
    Last Post: November 16th 2008, 08:41 PM
  4. Bayes rule solution check
    Posted in the Advanced Statistics Forum
    Replies: 4
    Last Post: February 3rd 2008, 02:29 PM
  5. Bayes Rule?
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: January 26th 2008, 03:26 PM

Search Tags


/mathhelpforum @mathhelpforum