1. ## Confidence interval

In a test of the effect of dampness on electric connections, 100 electric connections were tested under damp conditions and 150 were tested under dry conditions. Twenty of the damp connections failed and only 10 of the dry ones failed. Find a 95% confidence interval for the difference between the proportions of connections that fail when damp as opposed to dry.

I am having a very hard time getting through this problem.

2. what answer did you get?

3. i don't know how to start it

4. 95% confidence interval for the difference between the proportions is

$(p_1 - p_2)\pm Z_{\alpha /2}\times \sqrt{\frac{p_1 q_1}{N_1}+\frac{p_2 q_2}{N_2}}$

here your

$p_1=\frac{n_1}{N_1}$

$p_2=\frac{n_2}{N_2}$

$N_1=100, N_2=150$
$n_1=20, n_2=10$
$Z_{\frac{0.05}{2}}=1.96$

So solve accordingly.

PS: Check the correction i made.

5. how do i calculate q?

1-p=q
lost my mind for a sec

so i got 1.225, -.5668
does that seem right?

6. jabba1,

My bad. I guess even you dint realize that i have made a mistake in giving the values for $n_1$ and $n_2$.

And yes $q=1-p$.