I know that: and also that: Problem is: I am not able to prove the very last equality. That's all what I need. Seeking directions/help. Thanks a bunch!
Last edited by paolopiace; Mar 26th 2011 at 11:35 AM. Reason: Simplifying
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Hello, write the expansion for (you know, the beginning of the Taylor series... I don't remember what's the exact name) and then for the square root, consider it as power 1/2 and make another expansion ( )
Thanks, good idea but it seems it does not work (unless major mistakes): Let u = 1/n. Then: Let Then: Which means, the second term of the resulting series is the incorrect +1/(2n) instead of the wanted -1/(4n).
And what if you compute ?
...thanks...
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