I given that the pdf of a continuous random variable X is

$\displaystyle f(x) = e^{-x}$ for $\displaystyle x > 0$ and $\displaystyle 0 $ for $\displaystyle x \leq 0$

I have to find $\displaystyle P(X \leq 2 | X > 1)

$

Am I correct in thinking that

$\displaystyle P((X \leq 2) \cap (X > 1)) = P(1 < X \leq 2)$ ?