Results 1 to 3 of 3

Math Help - Posterior Distribution

  1. #1
    Newbie
    Joined
    Sep 2009
    Posts
    7

    Posterior Distribution

    If I have an X such that f(x|q) = q x (q -1) , q> 0, 0 < x <1 and assume that the prior distribution of q is exponential with mean 2, how do I go abotu finding the posterior distribution of q? I know that
    posterior pdf= (pdf(x given q) * pdf(q) )/ integral(numerator)dp ..... But in this case, I can't seem to get the denominator of the posterior distribution pdf to work out nicely. Help would be appreciated...

    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by be more View Post
    If I have an X such that f(x|q) = q x (q -1) , q> 0, 0 < x <1 and assume that the prior distribution of q is exponential with mean 2, how do I go abotu finding the posterior distribution of q? I know that
    posterior pdf= (pdf(x given q) * pdf(q) )/ integral(numerator)dp ..... But in this case, I can't seem to get the denominator of the posterior distribution pdf to work out nicely. Help would be appreciated...

    f(x|\theta)=\theta (1-\theta)x; \ x\in (0,1),\ \theta>0

    is not a conditional density for $$x

    CB
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Sep 2009
    Posts
    7
    I'm sorry, seems I didn't format it correctly. The X is from a pdf f(x|q) = q*x^(q-1) with the domains stated above. I'm interested in finding the posterior distribution of q.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 0
    Last Post: May 12th 2011, 03:43 PM
  2. Replies: 6
    Last Post: March 24th 2011, 05:57 PM
  3. normal distribution prior and posterior distribution proof
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: March 9th 2011, 06:12 PM
  4. Posterior distribution
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: February 24th 2010, 12:59 PM
  5. Posterior distribution
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: February 17th 2010, 04:10 AM

Search Tags


/mathhelpforum @mathhelpforum