# Posterior Distribution

• Mar 19th 2011, 08:09 AM
be more
Posterior Distribution
If I have an X such that f(x|q) = q x (q -1) , q> 0, 0 < x <1 and assume that the prior distribution of q is exponential with mean 2, how do I go abotu finding the posterior distribution of q? I know that
posterior pdf= (pdf(x given q) * pdf(q) )/ integral(numerator)dp ..... But in this case, I can't seem to get the denominator of the posterior distribution pdf to work out nicely. Help would be appreciated...

• Mar 19th 2011, 09:19 AM
CaptainBlack
Quote:

Originally Posted by be more
If I have an X such that f(x|q) = q x (q -1) , q> 0, 0 < x <1 and assume that the prior distribution of q is exponential with mean 2, how do I go abotu finding the posterior distribution of q? I know that
posterior pdf= (pdf(x given q) * pdf(q) )/ integral(numerator)dp ..... But in this case, I can't seem to get the denominator of the posterior distribution pdf to work out nicely. Help would be appreciated...

$f(x|\theta)=\theta (1-\theta)x; \ x\in (0,1),\ \theta>0$

is not a conditional density for $x$

CB
• Mar 19th 2011, 10:42 AM
be more
I'm sorry, seems I didn't format it correctly. The X is from a pdf f(x|q) = q*x^(q-1) with the domains stated above. I'm interested in finding the posterior distribution of q.