Y and V are independant, ,
a,b,c are constant.
Not sure if this is right
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If Y and V are independent, then E[V|Y]=E[V] and for a suitable function f, E[f(Y)|Y]=f(Y).
So there's just 1 simplification left.
why does E[f(y)/y]=f(y)?
in this case i would have thought that since f(y) depends explicitly on the values of y, this cannot be the case
It IS the case... f(Y) is Y-measurable.
Go back to your definitions...
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