Hi!
I have two dice values X, Y and should calculate the conditional distributions
X+Y given Y = 3 or 5
Y given X>Y
I don't know how to start with that. Can anyone give me a hint?
OK, I have your B already and I know how to calculate $\displaystyle P(X+Y=n|B)$ for every n, but how should the conditional distribution look like? Is it formula which can be derived from this or do I have to "see" what it should look like?
The only thing I can see is that P is $\displaystyle 2\cdot\frac{1}{12}, 4\cdot\frac{2}{12},2\cdot\frac{1}{12}$ between 4 and 11. I cannot come up with a formula that returns this behaviour.
So I was looking for something which isn't there.
How do I write the result?
$\displaystyle P(X+Y|Y \in \{3,5\}) = \{\frac{1}{12},\frac{1}{12},\frac{2}{12},\frac{2}{ 12},\frac{2}{12},\frac{2}{12},\frac{1}{12},\frac{1 }{12}$\}
By the way: thank you so far for your patience with me
This makes no sense because
1. probability is a number. Your right hand side is not a number.
2. What is the condition X + Y has to satisfy?
And what is $\displaystyle Y \in \{3,5\}$ meant to mean? Does it mean that Y = 3 or Y = 5?
Plato's replies say exactly what to do. I'm not sure what the trouble can stiil be ....? The result (that is, I assume, the answer) is given in your very first post!