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Kindly eloborate the solution
Since you wanted at leats one comment
We are doing this now in class! Well, I can tell you what they are doing generally but I would have to look into it a little more. This is functions of random variables and the technique implored here is the CDF. If you are familiar with the definition of CDF then afterwards it's just integration. What you see being integrated is the pdf of the normal distribution with mean zero and variance sigma^2. Gaussian distribution is the same as normal distribution and because there are two variables x and y, it's a double integral and to solve it it looks like they converted the integral into polar coordinates.
Once I go over my notes I'll be able to tell you exactly what's happening.
You should ask a more specific question. What part of the solution are you having problems with? The third equality is a polar transformation, if that is the source of confusion. Or perhaps it is the multiple typos in the solution.
This is probably not of much interest, but I feel compelled to say it.and
are chisquare, so
(by independence) which is exponential; square root an exponential to get a Rayleigh and we are done without using calculus
Chaotic, i am waiting for ur replyOriginally Posted by chaotic
Since you wanted at leats one comment
We are doing this now in class! Well, I can tell you what they are doing generally but I would have to look into it a little more. This is functions of random variables and the technique implored here is the CDF. If you are familiar with the definition of CDF then afterwards it's just integration. What you see being integrated is the pdf of the normal distribution with mean zero and variance sigma^2. Gaussian distribution is the same as normal distribution and because there are two variables x and y, it's a double integral and to solve it it looks like they converted the integral into polar coordinates.
Once I go over my notes I'll be able to tell you exactly what's happening.
Plz also comment on solution of theodds, he seems to be logical by giving simple solution
If you think of the bivariate normal that you get from a pair of independent zero mean equal variance RV you van think of this as a distribution over theplane, which can be rewritten as in polars then your
. Then the density of
comes out of the wash simply from the change of variables, in polars the symmetric bivariate normal distribution is constant as a function of
and Rayleigh in
CB
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