What is the probability of the union of 4 events? The events are:

E- hitting an even number on a dartboard= .0249

D- hitting a double P=.1049

N- hitting a number higher than 10 P=.0249

B- hitting a bullseye P= .007

I came up with:

1. P(E)+P(D)+P(N)+P(B)

**-**
2. [P (E $\displaystyle \cap$ D) + P(E $\displaystyle \cap$ N) +P (E $\displaystyle \cap$ B) + P(D $\displaystyle \cap$ N) + P(D $\displaystyle \cap$ B +[P(N $\displaystyle \cap$ B]

**+**
3. P(E $\displaystyle \cap$ D $\displaystyle \cap$ N)]+ P(D $\displaystyle \cap$ N $\displaystyle \cap$ B)]

**-**
4. P( E $\displaystyle \cap$ D$\displaystyle \cap$ N $\displaystyle \cap$ B)

I'm basically asking if I got the formula right for the probability of the union of 4 events.

Any help is appreciated