is 0,000013 the right answer?

P= P(Exactly 5 five from the first catagory)*P(Exactly 5 five from the second catagory)*P(Exactly 5 five the third catagory)=0,000013

P(Exactly 5 five from the first catagory)=nCr(15,5)*(0,15)^5*(1-0,15)^10

P(Exactly 5 five from the third catagory)=nCr(15,5)*(0,15)^5*(1-0,15)^10

P(Exactly 5 five from the second catagory)=nCr(15,5)*(0,68)^5*(1-0,68)^10