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Math Help - Likelihood function

  1. #1
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    Likelihood function

    Suppose an illness case during a single month has a poisson distribution with parameter \mu.
    The number of cases in January and February are 1 and 3 respectively.

    How can I find the likelihood function for this case?

    Following is my working: e^{-\mu}\mu*\frac{e^{-\mu}\mu^3}{3!}
    =  \frac{e^{-2\mu}{\mu^4}}{6}

    Am i right?
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  2. #2
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    Quote Originally Posted by noob mathematician View Post
    Suppose an illness case during a single month has a poisson distribution with parameter \mu.
    The number of cases in January and February are 1 and 3 respectively.

    How can I find the likelihood function for this case?

    Following is my working: e^{-\mu}\mu*\frac{e^{-\mu}\mu^3}{3!}
    =  \frac{e^{-2\mu}{\mu^4}}{6}

    Am i right?
    Yeah, that's fine. Don't forget I(\mu \ge 0) though.
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