# Math Help - Likelihood function

1. ## Likelihood function

Suppose an illness case during a single month has a poisson distribution with parameter $\mu$.
The number of cases in January and February are 1 and 3 respectively.

How can I find the likelihood function for this case?

Following is my working: $e^{-\mu}\mu*\frac{e^{-\mu}\mu^3}{3!}$
= $\frac{e^{-2\mu}{\mu^4}}{6}$

Am i right?

2. Originally Posted by noob mathematician
Suppose an illness case during a single month has a poisson distribution with parameter $\mu$.
The number of cases in January and February are 1 and 3 respectively.

How can I find the likelihood function for this case?

Following is my working: $e^{-\mu}\mu*\frac{e^{-\mu}\mu^3}{3!}$
= $\frac{e^{-2\mu}{\mu^4}}{6}$

Am i right?
Yeah, that's fine. Don't forget I(\mu \ge 0) though.