Hi,

http://i661.photobucket.com/albums/u...Untitled00.png

I don't understand (ii). Thanks for any input.

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- January 23rd 2011, 04:31 AMalgorithmEntropy questions
Hi,

http://i661.photobucket.com/albums/u...Untitled00.png

I don't understand (ii). Thanks for any input. - February 24th 2011, 11:53 AMisharp2h(1/6) = h(1/3) + h(1/2)
I think the correct response is found by formulating the question. The question asks to show that:

h(1/6) = h(1/3) + h(1/2)

By law of logarithms, this can be re-written as

h(1/6) = h((1/3)*(1/2))

h(1/6) = h(1/6)