Well, I'm a bit confused! That's what I thought at first too.
Since we are dealing with six number combinations, each one of which contains 6 possible combinations of five numbers, the total number of combinations of six containing all the combinations of five would be 324632 (35c5) / 6 = 54105 combinations of six; However, 35c6 would be 1623160.
So, if 30 were the answer to the first option, what would happen if we had all the combinations of 6 instead? Would it just be the same?
It's a translation.
Let me paraphrase.
We have all the possible combinations of five numbers from 1 to 35 (35c5) contained in combinations of six numbers.
for example: 1 2 3 4 5 6 (contains {1,2,3,4,5} {1,2,3,4,6} {1,2,3,5,6} {1,2,4,5,6} {1,3,4,5,6} {2,3,4,5,6})
What I want to know is how many of these -six- number combinations contain -five- specific numbers. Logically its 30. I'm confused however with the fact that every >1< combination of 6 contains 6 combinations of five!!
Hello, askjohn!
The wording is confusing.
All that emphasis on subsets of 5 numbers . . .
Given are all possible 6-number subsets of numbers from 1-35,
how many of these subsets contain 5 specific numbers?
What do you mean by "logically it's 30"? .Is that the correct answer?
Here's my reasoning . . .
The is one way to get the five specific numbers.
The sixth number can be any of the remaining 30 numbers.
Therefore, the answer is 30.