# Figuring out limits of integration when doing joint densities

• Jan 18th 2011, 01:37 PM
crabchef
Figuring out limits of integration when doing joint densities
The problem in question:

f(x,y)=24xy for 0<= x<=1, 0<=y<=1, 0<=x+y<=1, otherwise x=0

The goal is to show that f(x,y) is a joint probability fxn and I believe we do that by doubly integrating f(x,y) and showing the result equals 1.

I believe that the answer is: $\displaystyle \int_0^1\int_0^{1-y} \! 24xy \, \mathrm{d}x{d}y$, however I'm having trouble understanding the limits of integration. Why is it that we integrate from 0 to 1-y on x and from 0 to 1 on y?

Here's a similar problem I had earlier:

f(x,y)=2 0<x<y, 0<y<1

The problem asks the student to determine whether X,Y are independent. So, I set out to find the marginal distribution of x:

$\displaystyle \int_x^1 \! 2 \, \mathrm{d}y$ Why do we integrated from x to 1
$\displaystyle \int_0^y \! 2 \, \mathrm{d}x$ Why do we integrate from 0 to y

Could we switch the limits of integration as long as we adjust them for both X and Y? For example, could we integrate from 0 to 1 instead of x to 1 if we change the limits of integration on Y?

Thanks a bunch in advance...I hate probability
• Jan 18th 2011, 10:31 PM
matheagle
you need to review calculus three
To get started you need to draw the regions and that will explain the bounds
AND by the way I LOVE probability.
And this seems to be a problem from Walpole, I'm the first reviewer of Walpole in the introduction.