A bowl contains seven marbles of which are red while the others are blue. In order
to test the null hypothesis Ho : = 2 against HI : = 4, two of the marbles are
randomly drawn without replacement and the null hypothesis is rejected if and
only if both are red.
(a) What is the probability of committing a Type I error?
(b) What is the probability of committing a Type II error?
a) pr(2 red|theta=2) 2/7x1/6 = 1/21
b) pr(o red, 1 red|theta=4) = 3/7*2/6+4/7*3/6+3/7*4/6=5/7
can some1 explain this to me? i'm a bit lost. i know type 1 error is reject Ho when Ho is actually true.
for for a, i get 2 red marbles. so 2/7 and multiple it 1/6 chance? but why 1/6 chance?
and for b) type2 eror is failing to reject Ho when we actually should. just cant get my head around it some explaination would be great
This is what i got so far
Type I error = "false positive" = rejecting H_0 when H_0 is true
Type II error = "false negative" = accepting H_0 when H_0 is false = accepting H_0 when H_1 is true
So, in symbols:
Now you go back and plug in what is meant by reject/accept H_0, and the hypotheses H_0 and H_1 in this problem, to get
and then it is just a matter of calculating them, as in the solution.
then, are my numbers correct? just a bit lost in how to interpret the numbers within the question to get the answer.