if x,y are independent, identically distributed r.v.-s with mean u and variance sigma^2 , find E[(X-Y)^2].
have tried but dont know how you could use x-y
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Now use that E[XY]=E[X]E[Y] ...since X,Y are independant.
im a little confused..... i thought the question asked to find that formula using the fact mean is u and variance is sigma squared. Im probably wrong just dont know how to finish question ...thanks so much for taking time!!!
Ok trying figure this out I can't figure how you get to E(x-y)^2 I'm not sure am I just missing something simple or how you get it. Workin on it but getting no where. Is E(x-y)^2 a specific formula??
Look at post no. 2 by DinkyDoe. It has already been found out for you!
He seemed to multiply out then simplify , do I use your info before this I'm failing to see the connection sorry thanks for helpin
Follow his instructions first, and then use my info!
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