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Math Help - consecutive cases

  1. #1
    Junior Member
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    May 2010
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    mean and variance

    Hi I have this question, which has completely stumped me..Does anyone has any suggestions on how to do it?

    Can anyone give any hint?

    Thanks!
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  2. #2
    Senior Member Sambit's Avatar
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    consider it as a geometric distribution with probability of success (that is, probability of finding a disease) = p^3
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  3. #3
    Junior Member
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    I still am not sure if this is really a geometric distribution:

    so, am i supposed to use the pmf  p^3(1-p)^x??

    that would mean we are calculating for  p^3 , \mbox{and} , q^3. thats either 3 success or 3 failures.. but we do have  ppq (2 successes and 1 failure) and pqq(1 success and 2 faliures) as well. Dont we need to count those? Deriving the pmf using these scenarios is really confusing me.
    Last edited by chutiya; October 26th 2010 at 07:28 AM.
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