Triangular distribution

**noob mathematician** · October 20th 2010, 08:52 AM

Let X be a r.v. with density $f(x)=(1-|x|)1_{(-1,1)}(x)$ . How do I show that $\varphi(u)=\frac{2(1-cosu)}{u^2}$ .

Am i on the right track to relate it with $cosx=\frac{1}{2}(e^{ix}+e^{-ix})$ and $sinx=\frac{1}{2i}(e^{ix}-e^{-ix})$

**pkliber** · October 22nd 2010, 02:32 AM

Rather use e^{iux} = sin(ux) + i cos(ux)

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