n people put their watch in the center of a room where the watches are mixed
together. Each person then randomly selects one. Let X represent the number that select their own watch. Find the expected value and variance of X.
I found the expedted value to be 1. ( sum to n 1/n*1). So variance i have
sum 1/n(x_i - 1)^2 = 0
is the variance correctly 0?