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Math Help - pdf of a RV

  1. #1
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    pdf of a RV

    the pdf of a random variable is geven as f(x)= \frac{32}{x^3} if x \geq 4, and 0 otherwise.

    I am supposed to find P(X \geq 10)

    what I did was : P(X \geq 10) = 1 - F(10) = \int_{10}^{\infty} f(y) \mbox{dy}

    is that the correct way?

    thanks
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  2. #2
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    Quote Originally Posted by chutiya View Post
    the pdf of a random variable is geven as f(x)= \frac{32}{x^3} if x \geq 4, and 0 otherwise.

    I am supposed to find P(X \geq 10)

    what I did was : P(X \geq 10) = 1 - F(10) = \int_{10}^{\infty} f(y) \mbox{dy}

    is that the correct way?

    thanks
    Yes.
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