Math Help - pdf of a RV

1. pdf of a RV

the pdf of a random variable is geven as $f(x)= \frac{32}{x^3}$ if $x \geq 4$, and 0 otherwise.

I am supposed to find $P(X \geq 10)$

what I did was : $P(X \geq 10) = 1 - F(10) = \int_{10}^{\infty} f(y) \mbox{dy}$

is that the correct way?

thanks

2. Originally Posted by chutiya
the pdf of a random variable is geven as $f(x)= \frac{32}{x^3}$ if $x \geq 4$, and 0 otherwise.

I am supposed to find $P(X \geq 10)$

what I did was : $P(X \geq 10) = 1 - F(10) = \int_{10}^{\infty} f(y) \mbox{dy}$

is that the correct way?

thanks
Yes.