Suppose that P(A)=a and P(B)=b. show that P(A|B)>=(a+b-1)/b.
http://www.mathhelpforum.com/math-he...ial-19060.html
Please, please learn to post in symbols? You can use LaTeX tags.
[tex]P(A|B)\ge \dfrac{a+b-1}{b} [/tex] gives $\displaystyle P(A|B)\ge \dfrac{a+b-1}{b} $.
Having misread this posting, I wasted a good bit of time.
All it takes is to notice $\displaystyle P(A\cap B)\ge P(A)+P(B)-1$.