# Expected Value

• Sep 9th 2010, 09:54 PM
aj22315
Expected Value

Given f(x) = 2x+3, Find E(X) for 0 < x < 2

Attachment 18872

So the answer is 34/3. Is that correct?
• Sep 9th 2010, 10:25 PM
Amer
it is true
• Sep 10th 2010, 05:14 PM
matheagle
nope, this does not make sense
I have no idea what x- and x+ are.
But that is not a valid density

$\int_{-\infty}^{\infty}f(x)dx=1$ and $E(X)=\int_{-\infty}^{\infty}xf(x)dx$

where as $\int_0^2(2x+3)dx=10$