Hello, this is my first time posting here. I am studying for the P1 actuarial exam Thank you for any help X = # of times you need to roll to get the first 5. E(X ∣ X > 2) = (1/(1/6)) + 2 How do I get this ^ solution ^
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Originally Posted by CaptainLorax Hello, this is my first time posting here. I am studying for the P1 actuarial exam Thank you for any help X = # of times you need to roll to get the first 5. E(X ∣ X > 2) = (1/(1/6)) + 2 How do I get this ^ solution ^ Lets assume you are talking rolling a fair die. The prior history of rolls does not effect the future outcomes, so: and: CB
thank you very much
actually I still don't understand how the end of your equation = 1/(1/6)
Originally Posted by CaptainLorax actually I still don't understand how the end of your equation = 1/(1/6) To get the first 5 on the n-th roll requires that you roll n-1 non-fives with probability 5/6 and the last roll is a 5 with probability 1/6 CB
now I just have to figure out how to send a virtual thanks your way edit-found it
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