Given the contingency table at the bottom, estimate the percentage of all people over the age of 50+ who get their news from the internet. Assume $\displaystyle H_o$ is true.

First I defined $\displaystyle H_o$: the distribution of age groups in each news source is the same in each age category

I believe that I'm looking for the expected value, but I don't know the population size. So I did $\displaystyle EV=\frac{76}{95+83+76}x100%=29.9%$ is this right? 1.