A given honest is launched 100 times in a row. What is the probability that in 18 or more of these releases occur side 2?

I find:

p = 1/6

$\displaystyle Z = \frac{17,5 - (100* \frac{1}{6})}{\sqrt{100 * \frac{1}{6} * \frac{5}{6}}} = 0,22 -> 0,587064$

But the answer is: 0,4129