In a multiple choice test have 200 questions, each with four possible answers, of which only one is correct. What is the probability that a student hit between 25 and 30 of 80 questions among 200 of which he knows nothing?

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- June 20th 2010, 02:48 PMApprentice123approximations of distributions
In a multiple choice test have 200 questions, each with four possible answers, of which only one is correct. What is the probability that a student hit between 25 and 30 of 80 questions among 200 of which he knows nothing?

- June 20th 2010, 02:51 PMSpringFan25
You've identified what you need to do in the title (approximations of distributions). Where are you stuck?

- June 20th 2010, 02:53 PMundefined
I'm confused by the wording. Is the number 200 irrelevant, and we're just considering the 80 questions for which the student guesses? Also, is "between 25 and 30" inclusive, as in {25,26,27,28,29,30} or exclusive as in {26,27,28,29}? I would assume inclusive, but it's nice if it's specified.

- June 20th 2010, 02:59 PMApprentice123
My attempt

p = 25% = 0,25

P(25 < X < 30)

P(X>25) = P(X > 25,5) by approximations of distributions

Z1 = 1,42 -> 0,922196

P(X<30) = P(X < 29,5) by approximations of distributions

Z2 = 2,45 -> 0,992857

Z2 - Z1 = 0,070661

But the answer is 0,1196 - June 20th 2010, 03:22 PMSpringFan25
You have tried to do: P(25 < X < 30) = P(X<30) - P(X>25)

it should be

I assume the question actually wants which can be worked out as follows

We will say this is approximated by

= 0.9967

= 0.877361

.9967-.877361 = .119286

I assume the difference between me and the textbook is due to rounding. - June 20th 2010, 03:30 PMApprentice123
You not used approximations of distributions ?

- June 20th 2010, 03:32 PMSpringFan25
indeed i did...

Quote:

Originally Posted by**Me**

I have made minor changes to the original post in case it wasn't clear. - June 20th 2010, 04:31 PMApprentice123
Ohh yes. Thank you