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Math Help - Binomial distribution.

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    Binomial distribution.

    In a study of recognition of a mark, 95% of consumers recognize the brand. But beyond 15 randomly selected consumers, only 10 recognize the brand.

    What is the probability of obtaining a maximum of 10 consumers recognize the brand among the 15 selected?
    Last edited by mr fantastic; June 3rd 2010 at 05:13 PM. Reason: Re-titled.
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    What does "beyond 15 randomly selected. . ." mean? Does that mean someone asked 15 people and only 10 people recognized the brand? Not familiar with the wording.

    If you assume that the population proportion is .95 recognize and .05 do not recognize, then this is a simple binomial distribution where you are calculating the probability of getting exactly 10 successes out of 15 tries. If you need help further than that, be sure to note where you are getting confused.
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    Quote Originally Posted by ANDS! View Post
    What does "beyond 15 randomly selected. . ." mean? Does that mean someone asked 15 people and only 10 people recognized the brand? Not familiar with the wording.

    If you assume that the population proportion is .95 recognize and .05 do not recognize, then this is a simple binomial distribution where you are calculating the probability of getting exactly 10 successes out of 15 tries. If you need help further than that, be sure to note where you are getting confused.
    In a brand awareness 95% of consumers recognize the brand name "ABC".
    However, among 15 randomly selected consumers only 10 recognize the brand name "ABC".
    What is the probability of obtaining 10 consumers recognize the brand name "ABC" of the 15 selected?
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    Quote Originally Posted by Apprentice123 View Post
    In a brand awareness 95% of consumers recognize the brand name "ABC".
    However, among 15 randomly selected consumers only 10 recognize the brand name "ABC".
    What is the probability of obtaining 10 consumers recognize the brand name "ABC" of the 15 selected?
    From this wording it seems we want the probability that exactly 10 consumers recognize the brand out of 15 randomly selected, rather than at most 10.

    If we assume an infinitely large population, then when picking out random consumers without replacement, the event that one consumer recognizes "ABC" is independent from the event that another consumer recognizes "ABC," always with probability 0.95.

    So the probability we're after is

    P(X = 10) = \binom{15}{10}(1-0.95)^{10}(0.95)^5.

    See here for more info.
    Last edited by undefined; June 3rd 2010 at 02:24 PM. Reason: typo
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    Quote Originally Posted by undefined View Post
    From this wording it seems we want the probability that exactly 10 consumers recognize the brand out of 15 randomly selected, rather that at most 10.

    If we assume an infinitely large population, then when picking out random consumers without replacement, the event that one consumer recognizes "ABC" is independent from the event that another consumer recognizes "ABC," always with probability 0.95.

    So the probability we're after is

    P(X = 10) = \binom{15}{10}(1-0.95)^{10}(0.95)^5.

    See here for more info.
    But the answer is 0,0006146 I not find
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    Quote Originally Posted by Apprentice123 View Post
    But the answer is 0,0006146 I not find
    I don't get that answer either. I believe my method is correct. My guess (call it arrogance if you like) is that either the book is wrong, or not properly worded. I'm assuming you typed it out exactly as written. Anyone else care weigh in on this?
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    Quote Originally Posted by undefined View Post
    I don't get that answer either. I believe my method is correct. My guess (call it arrogance if you like) is that either the book is wrong, or not properly worded. I'm assuming you typed it out exactly as written. Anyone else care weigh in on this?
    My interpretation of the problem:
    - 95% of consumers know "ABC"
    - We selected 15 consumers
    - Of these 15, only 10 known "ABC"

    The question is:
    - Of these 15, what is the probability of 10 consumers know "ABC" ?
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    Quote Originally Posted by Apprentice123 View Post
    My interpretation of the problem:
    - 95% of consumers know "ABC"
    - We selected 15 consumers
    - Of these 15, only 10 known "ABC"

    The question is:
    - Of these 15, what is the probability of 10 consumers know "ABC" ?
    Not sure I follow you on that. If it is known that 10 of the 15 consumers know "ABC," then the probability that 10 of the 15 consumers know "ABC" is 1, or 100%.
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    Quote Originally Posted by undefined View Post
    Not sure I follow you on that. If it is known that 10 of the 15 consumers know "ABC," then the probability that 10 of the 15 consumers know "ABC" is 1, or 100%.
    Sorry. The question is:

    Of the 15 selected, what is the probability of have at MAXIMUM 10 consumers know "ABC" ?
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  10. #10
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    Quote Originally Posted by Apprentice123 View Post
    Sorry. The question is:

    Of the 15 selected, what is the probability of have at MAXIMUM 10 consumers know "ABC" ?
    No problem! I get the book answer now.

    Let X be the random variable: how many people of the 15 know "ABC."

    We have P(X\leq 10) = 1 - P(X \geq 11) = 1 - P(X = 11) - \cdots - P(X = 15)

     = 1 - \binom{15}{11}(0.95)^{11}(0.05)^4 - \binom{15}{12}(0.95)^{12}(0.05)^3 -
    \binom{15}{13}(0.95)^{13}(0.05)^2 - \binom{15}{14}(0.95)^{14}(0.05)^1 - \binom{15}{15}(0.95)^{15}(0.05)^0

    \approx 0.00061468286968
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    Quote Originally Posted by undefined View Post
    No problem! I get the book answer now.

    Let X be the random variable: how many people of the 15 know "ABC."

    We have P(X\leq 10) = 1 - P(X \geq 11) = 1 - P(X = 11) - \cdots - P(X = 15)

     = 1 - \binom{15}{11}(0.95)^{11}(0.05)^4 - \binom{15}{12}(0.95)^{12}(0.05)^3 -
    \binom{15}{13}(0.95)^{13}(0.05)^2 - \binom{15}{14}(0.95)^{14}(0.05)^1 - \binom{15}{15}(0.95)^{15}(0.05)^0

    \approx 0.00061468286968
    Now I understand. Thank you very much.
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