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**electricalphysics** Question:

If Y has a geometric distribution with success probability .3, what is the largest value, y0, such

that P(Y > y0) ≥ .1?

Attempt:

So i represented the probability of the random variable as a summation

once working with the other end =>

summation from y0 =0 to y0-1 of q^y0-1 p < 0.9

with the change of variables l= y0-1

summation from l=0 to l of q^l p < 0.9

now finding the partial sum of the geometric series

p/(1-q) < 0.9

0.3/ 0.3 < 0.9

i'm stuck here ? how do i get the value for y0 ?