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Math Help - red followed by a yellow

  1. #1
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    red followed by a yellow

    there are 3 red spaces, 1 blue space, 3 yellow spaces, and one green space for a total of 8 spaces on a spinner. What is the probability of getting a red spin followed by a yellow spin in two spins?


    I am new to probability, so I wanted to check out a couple of my homework questions.

    Here is what I think:
    There are n(s) = 8*8 = 64 possible spins in two total spins
    n(r,y) = 3C1 * 3C1 = 9 possible reds followed by a yellow

    so the probability of spinning a red then yellow in two spins is 9/64???
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  2. #2
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    Hello, ihavvaquestion!

    Your reasoning and your answer are both correct!


    Here's another approach . . .

    The probability that the first spin is Red is: \frac{3}{8}

    The probability that the second spin is Yellow is: \frac{3}{8}

    Therefore: . P(\text{Red, then Yellow}) \;=\;\frac{3}{8}\cdot\frac{3}{8} \;=\;\frac{9}{64}

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