Hello, ihavvaquestion!
Your reasoning and your answer are both correct!
Here's another approach . . .
The probability that the first spin is Red is:
The probability that the second spin is Yellow is:
Therefore: .
there are 3 red spaces, 1 blue space, 3 yellow spaces, and one green space for a total of 8 spaces on a spinner. What is the probability of getting a red spin followed by a yellow spin in two spins?
I am new to probability, so I wanted to check out a couple of my homework questions.
Here is what I think:
There are n(s) = 8*8 = 64 possible spins in two total spins
n(r,y) = 3C1 * 3C1 = 9 possible reds followed by a yellow
so the probability of spinning a red then yellow in two spins is 9/64???