A gambler bets a stake of 1 repeatedly on a game. They lose with probability 1/2 in which case the stake is lost. If the gambler wins they are, with equal probability, either returned their 1 stake or they recieve their 1 and an additional 1.
Starting with k the gambler playes the game repeatedly until they either go bankrupt or reach N, where N greater or equal to k.
Let B_{k} be the event that the gambler eventually goes bankrupt.

For k=1,2,...N-1 show that:
3P(B_{k})=P(B_{k+1})+2P(B_{k-1})



I know the answer to this should be pretty simple, but I can't get it to work. A thorough solution would be of much help! Thanks