In a company, we manufacture metal poles. Suppose the length of a pole is a random variable X, with meanand probability density function
. Poles are cut to obtain an exact length L. If the initial length of the pole is less than L, the entire pole is lost. If it is greater than L, the pole will be cut down to L, and the section left over is lost.
We are interested in random variable Y, defined as the length of each piece lost.
(i) Sketch the graph of y (values of Y) as a function of x (values of X), and deriveas a function of
and
.
(ii) Suppose X follows a normal distribution with meanand variance
. Show there exists a value
of
which makes
minimum.
(iii) Let L = 2m,= 0.02m. What is the value of
which minimizes the amount of lost material.
Thanks a lot for your help!
Original Post:
http://www.mathhelpforum.com/math-he...obability.html
I have the same question here, and I am stuck at part ii, I have done the first part and get the results
m(Y) = m(X) - L + LF(x)
to find the min. m(Y) I think I have to differentiate both sides...but how can I differentiate "LF(x)"...? And I couldnt find any solution in the original post.
Can anyone help plz?


LinkBack URL
About LinkBacks