Suppose X has the following probability distribution: X P(X) 0 0.5 1 .25 2 .25 Find P(X<2|X>1) Multiple choice answers are: A) .5 B) 1 C) 0 D) .25 E) .75 If you could tell/show me how to get the answer I'd appreciate it.
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I'd say $\displaystyle P(x<2|x>1) = \frac{P(x<2\cap x>1)}{P(x>1)} =\frac{0}{0.25} = 0$
Thank you so much! I see it now, out of those three numbers none can be less than 2 AND greater than 1, so 0 has to be it!
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