Thread: URGENT help Transformations

Suppose that X1,...,Xn is a random sample from a Weibull distribution, WEI(Q,2)

Show that 2*(sum of all Xi)^2/Q^2 is chi square distribution with 2n degrees of freedom.

I have no idea how to look at this problem
Any ideas?


Any help is greatly appreciated

first use the moment generating function to obtain the density of the sum

I tried that already but i feel like i can not get it right or i am missing something....How would I find solve this integral-it doesn't seem like it looks like any other distribution?

Thanks

show your work
I'm not even sure how you're writing your density