1. ## bi(n;x,θ)

hello
if x~bi(n;x,θ) then for which θ the probability is the max?

2. Originally Posted by abdolah
hello
if x~bi(n;x,θ) then for which θ the probability is the max?
Please explain you notation and preferably the exact wording of the problem.

CB

3. ok i mean this:
if we have binomial disribution with parameter x and teta(the probability of each victory) and n then for which teta the binomial probability is the max?

4. Originally Posted by abdolah
ok i mean this:
if we have binomial disribution with parameter x and teta(the probability of each victory) and n then for which teta the binomial probability is the max?
You have a RV $N \sim B(x,\theta)$

Now you ask for what value of $\theta$ is:

$b(n;x,\theta)=\frac{n!}{x!(n-x)!} \theta^n (1-\theta)^{n-1}$

maximised.

Start by observing the required $\theta$ is a solution of:

$\frac{\partial}{\partial \theta}b(n;x,\theta)=0$

CB